Eureka Math Grade 4 Module 5 Lesson 29 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 5 Lesson 29 Answer Key

Eureka Math Grade 4 Module 5 Lesson 29 Problem Set Answer Key

Question 1.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. 2\(\frac{1}{12}\) + 1\(\frac{7}{8}\) ≈ ____40/12________

Answer:
2(1/12) + 1(7/8) = 40/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(1/12) + 1(7/8).
12 x 2 = 24.
1 x 8 = 8.
24 + 1/12 = 25/12.
8 + 7/8 = 15/8.
25/12 + 15/8 = 40/12.

b. 1\(\frac{11}{12}\) + 5\(\frac{3}{4}\) ≈ ____46/4_________

Answer:
1(11/12) + 5(3/4) = 46/4.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
1(11/12) + 5(3/4).
12 x 1 = 12.
5 x 4 = 20.
12 + 11/12 = 23/12.
20 + 3/4 = 23/4.
23/12 + 23/4 = 46/4.

c. 8\(\frac{7}{8}\) – 2\(\frac{1}{9}\) ≈ ____52/9________

Answer:
8(7/8) – 2(1/9) = 52/9.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
8(7/8) – 2(1/9).
8 x 8 = 64.
2 x 9 = 18.
64 + 7/8 = 71/8.
18 + 1/9 = 19/9.
71/8 – 19/9 = 52/9.

d. 6\(\frac{1}{8}\) – 2\(\frac{1}{12}\) ≈ __________

Answer:
6(1/8) – 2(1/12) = 24/12.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
6(1/8) – 2(1/12).
6 x 8 = 48.
2 x 12 = 24.
48 + 1/8 = 49/8.
24 + 1/12 = 25/12.
49/8 – 25/12 = 24/12.

e. 3\(\frac{3}{8}\) + 5\(\frac{1}{9}\) ≈ _____73/9______

Answer:
3(3/8) + 5(1/9) = 73/9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(3/8) + 5(1/9).
8 x 3 = 24.
5 x 9 = 45.
24 + 3/8 = 27/8.
45 + 1/9 = 46/9.
27/8 + 46/9 = 73/9.

Question 2.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. \(\frac{16}{5}\) + \(\frac{11}{4}\) ≈ ______

Answer:
16/5 + 11/4 = 6.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
16/5 + 11/4.
16/5 = 3.2.
11/4 = 2.75.
3.2 + 2.75 = 5.95.
16/5 + 11/4 = 5.95.

b. \(\frac{17}{3}\) – \(\frac{15}{7}\) ≈ _______

Answer:
17/3 + 15/7 = 8.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17/3 + 15/7.
17/3 = 5.6.
15/7 = 2.14.
5.6 + 2.14 = 7.74.
17/3 + 15/7 = 7.74.

c. \(\frac{59}{10}\) + \(\frac{26}{10}\) ≈ _______

Answer:
59/10 + 26/10 = 8.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
59/10 + 26/10.
59/10 = 5.9.
26/10 = 2.6.
5.9 + 2.6 = 8.5.
59/10 + 26/10 = 8.

Question 3.
Montoya’s estimate for 8\(\frac{5}{8}\) – 2\(\frac{1}{3}\) was 7. Julio’s estimate was 6\(\frac{1}{2}\). Whose estimate do you think is closer to the actual difference? Explain.

Answer:
8(5/8) -2(1/3) = 62/5.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
8(5/8) – 2(1/3).
8 x 8 = 64.
2 x 3 = 6.
64 + 5/8 = 69/8.
6 + 1/3 = 7/3.
69/8 – 7/3 = 62/5.

Question 4.
Use benchmark numbers or mental math to estimate the sum or difference.
a. 14\(\frac{3}{4}\) + 29\(\frac{11}{12}\)

Answer:
14(3/4) + 29(11/12) = 418/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
14(3/4) + 29(11/12).
14 x 4 = 56.
29 x 12 = 348.
56 + 3/4 = 59/4.
348 + 11/12 = 359/12.
59/4 + 359/12 = 418/12.

b. 3\(\frac{5}{12}\) + 54\(\frac{5}{8}\)

Answer:
3(5/12) + 54(5/8) = 478/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(5/12) + 54(5/8).
12 x 3 = 36.
54 x 8 = 432.
36 + 5/12 = 41/12.
432 + 5/8 = 437/8.
41/12 + 437/8 = 478/12.

c. 17\(\frac{4}{5}\) – 8\(\frac{7}{12}\)

Answer:
17(4/5) – 8(7/12) = 192/60.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17(4/5) – 8(7/12).
17 x 5 = 85.
12 x 8 = 96.
85 + 4/5 = 89/5.
96 + 7/12 = 103/12.
89/5 + 103/12 = 192/60.

d. \(\frac{65}{8}\) – \(\frac{37}{6}\)

Answer:
65/8 – 37/6 = 4.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
65/8 – 37/6.
65/8 = 8.1.
37/6 = 6.1.
8.1 – 6.1 = 4.1.
65/8 – 37/6 = 4.1.

Eureka Math Grade 4 Module 5 Lesson 29 Exit Ticket Answer Key

Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
Question 1.
2\(\frac{9}{10}\) + 2\(\frac{1}{4}\) ≈ _________

Answer:
2(9/10) + 2(1/4) = 38/40.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(9/10) + 2(1/4).
2 x 10 = 20.
2 x 4 = 8.
20 + 9/10 = 29/10.
8 + 1/4 = 9/4.
29/10 + 9/4 = 38/40.

Question 2.
11\(\frac{8}{9}\) – 3\(\frac{3}{8}\) ≈ _________

Answer:
11(8/9) – 3(3/8) = 80/72.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
11(8/9) – 3(3/8).
11 x 9 = 99.
3 x 8 = 24.
99 + 8/9 = 107/9.
24 + 3/8 = 27/8.
107/9 – 27/8 = 80/72.

Eureka Math Grade 4 Module 5 Lesson 29 Homework Answer Key

Question 1.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. 3\(\frac{1}{10}\) + 1\(\frac{3}{4}\) ≈ ___________

Answer:
3(1/10) + 1(3/4) = 38/40.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(1/10) + 1(3/4).
10 x 3 = 30.
1 x 4 = 4.
30 + 1/10 = 31/10.
4 + 3/4 = 7/4.
31/10 + 7/4 = 38/40.

b. 2\(\frac{9}{10}\) + 4\(\frac{4}{5}\) ≈ __________

Answer:
2(9/10) + 4(4/5) = 53/50.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(9/10) + 4(4/5).
2 x 10 = 20.
5 x 4 = 20.
20 + 9/10 = 29/10.
20 + 4/5 = 24/5.
29/10 + 24/5 = 53/50.

c. 9\(\frac{9}{10}\) – 5\(\frac{1}{5}\) ≈ __________

Answer:
9(9/10) – 5(1/5) = 73/5.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
9(9/10) – 5(1/5).
9 x 10 = 90.
5 x 5 = 25.
90 + 9/10 = 99/10.
25 + 1/5 = 26/5.
99/10 – 26/5 = 73/5.

d. 4\(\frac{1}{9}\) – 1\(\frac{1}{10}\) ≈ __________

Answer:
4(1/9) – 1(1/10) = 48/10.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
4(1/9) – 1(1/10).
9 x 4 = 36.
1 x 10 = 10.
36 + 1/9 = 37/9.
10 + 1/10 = 11/10.
37/9 + 11/10 = 48/10.

e. 6\(\frac{3}{12}\) + 5\(\frac{1}{9}\) ≈ _______

Answer:
6(3/12) + 5(1/9) = 121/9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
6(3/12) + 5(1/9).
6 x 12 = 72.
5 x 9 = 45.
72 + 3/12 = 75/12.
45 + 1/9 = 46/9.
75/12 + 46/9 = 121/9.

Question 2.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. \(\frac{16}{3}\) + \(\frac{17}{8}\) ≈ __________

Answer:
16/3 + 17/8 = 7.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
16/3 + 17/8.
16/3 = 5.3.
17/8 = 2.1.
5.3 + 2.1 = 7.4.
16/3 + 17/8 = 7.

b. \(\frac{17}{3}\) – \(\frac{15}{4}\) ≈ __________

Answer:
17/3 – 15/4 = 9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17/3 – 15/4.
17/3 = 5.6.
15/4 = 3.7.
5.6 + 3.7 = 9.3.
15/4 + 17/3 = 9.

c. \(\frac{57}{8}\) + \(\frac{26}{8}\) ≈ __________

Answer:
57/8 + 26/8 = 10.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
57/8 + 26/8.
57/8 = 7.1.
26/8 = 3.2.
7.1 + 3.2 = 10.3.
57/8 + 26/8 = 10.

Question 3.
Gina’s estimate for 7\(\frac{5}{8}\) – 2\(\frac{1}{2}\) was 5. Dominick’s estimate was 5\(\frac{1}{2}\). Whose estimate do you think is closer to the actual difference? Explain.

Answer:
7(5/8) – 2(1/2) = 56/4.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
7(5/8) – 2(1/2).
8 x 7 = 56.
2 x 2 = 4.
56 + 5/8 = 61/8.
4 + 1/2 = 5/2.
61/8 – 5/2 = 56/4.

Question 4.
Use benchmark numbers or mental math to estimate the sum or difference.
a. 10\(\frac{3}{4}\) + 12\(\frac{11}{12}\)

Answer:
10(3/4) + 12(11/12) = 199/3.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
10(3/4) + 12(11/12).
10 x 4 = 40.
12 x 12 = 144.
40 + 3/4 = 43/4.
144 + 11/12 = 156/12.
43/4 + 156/12 = 199/3.

b. 2\(\frac{7}{10}\) + 23\(\frac{3}{8}\)

Answer:
2(7/10) + 23(3/8) = 214/80.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(7/10) + 23(3/8).
2 x 10 = 20.
23 x 8 = 184.
20 + 7/10 = 27/10.
184 + 3/8 = 187/8.
27/10 + 187/8 = 214/80.

c. 15\(\frac{9}{12}\) – 8\(\frac{11}{12}\)

Answer:
15(9/12) – 8(11/12) = 82/12.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
15(9/12) – 8(11/12).
15 x 12 = 180.
8 x 12 = 96.
180 + 9/12 = 189/12.
96 + 11/12 = 107/12.
189/12 – 107/12 = 82/12.

d. \(\frac{56}{7}\) – \(\frac{31}{8}\)

Answer:
56/7 – 31/8 = 4.2.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
56/7 – 31/8.
56/7 = 8.
31/8 = 3.8.
8 – 3.8 = 4.2.
56/7 – 31/8 = 4.2.

Eureka Math Grade 4 Module 5 Lesson 29 Answer Key (2024)

FAQs

What grade does Eureka math go to? ›

Eureka Math Print Materials

New Learn, Practice, Succeed student workbooks (Grades K–8) offer teachers multiple ways to differentiate instruction, provide extra practice, and assess student learning, and are available in Armenian, Arabic, French, Korean, Mandarin, and Spanish.

What is the purpose of the concept development in Eureka math? ›

The concept development is generally comprised of carefully sequenced problems centered within a specific topic to begin developing mastery via gradual increases in complexity.

What is the hardest math grade? ›

Generally speaking, the most rigorous math courses in high school include Advanced Placement (AP) Calculus AB and BC, AP Statistics, and for some, Multivariable Calculus (which might be offered at your school or at a local college).

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

How long should an Eureka math lesson be? ›

Eureka Math is 1 hour for all grade levels (except in Kindergarten lessons are 50 minutes). We have always designed our elementary day with 1 hour dedicated to mathematics instruction.

Is Eureka Math still free? ›

Eureka Math Is Free

The curriculum is accompanied by a selection of instructional materials and support resources for teachers at no additional cost.

What are the parts of the Eureka math lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket). Each component described serves a distinct purpose.

What math is 8th grade level? ›

Eighth-grade math is typically a course in pre-algebra to help prepare students for high school algebra.

What math level is 5th grade? ›

In fifth grade, students focus on adding, subtracting, multiplying, and dividing whole numbers, fractions, and decimals. Your kid will become fluent with computing these types of numbers and understanding the relationship between them. Students should also be able to use these numbers in real-world scenarios.

What grade does prodigy math go up to? ›

With 1,500+ curriculum-aligned math skills for 1st to 8th grade, Prodigy Math is so much more than a game. Prodigy Math is an engaging game-based learning platform that's dedicated to improving students' confidence and achievements in math.

What is the highest math class there is? ›

Wrap up with Calculus, the highest level of math offered by many high schools and often considered the gold standard of pre-college math preparation.

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